Difference between revisions of "Interview Preparation Strings"
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					| Proj user14 (talk | contribs)  (→Reverse words in a string) | Proj user14 (talk | contribs)   (→Find the last word in a string) | ||
| Line 75: | Line 75: | ||
| == Find the last word in a string == | == Find the last word in a string == | ||
| − | + | If given string is "Dreams don't work unless you do " | |
| + | <BR/> | ||
| + | Output needed : "do" | ||
| + | <BR/> | ||
| + | To get the desired output we will use one pointer which points at the end of string and we will transverse it till we get our first blank space between last 2 words in string. | ||
| + | <BR/> | ||
| + | <syntaxhighlight lang="c"> | ||
| + | char* last_word_in_string(char *s) | ||
| + | { | ||
| + | 	int i=0; | ||
| + | 	char* last; | ||
| + | 	const int len= strlen(s) -1; | ||
| + | 	char *j = s + len; | ||
| + | /* | ||
| + |  * If last letter of string is blank space then it will be avoided. | ||
| + |  */ | ||
| + | 	if (*(s+len) == ' ') | ||
| + | 	{ | ||
| + | 		j = j-1; | ||
| + | 	} | ||
| + | 	while(*j) | ||
| + | 	{ | ||
| + | |||
| + | 		if ( *j== ' ') | ||
| + | 		{ | ||
| + | 			j++; | ||
| + | 			break; | ||
| + | 		} | ||
| + | 		j--; | ||
| + | 		i++; | ||
| + | |||
| + | 	} | ||
| + | 	return j; | ||
| + | } | ||
| + | |||
| + | </syntaxhighlight> | ||
| <BR/> | <BR/> | ||
| + | |||
| == TODO : More string questions == | == TODO : More string questions == | ||
Revision as of 12:05, 27 November 2016
Contents
Reverse a string
void reverse_str(char *s)
{
    const int len = strlen(s);
    const int mid = len / 2;
    for (int i = 0, j=len-1; i < mid; i++, j--) {
        char c = s[i];
        s[i]   = s[j];
        s[j]   = c;
    }
}
Reverse words in a string
If string to be reversed is "where there is a will there is a way"
Output needed : "way a is there will a is there where"
To reverse the words in a string , we will follow below steps:
1) First, we will reverse each word in the string as "erehw ereht si a lliw ereht si a yaw"
2) Second, we will reverse this string by letter to get the desired output.
We are going to use previous reverse_str function with one more parameter "length" as below:
void reverse_str(char *s ,int len)
{
    int i,j;
	char temp;
	j= len - 1;
	int mid = len/2;
	for(i=0;i<mid;i++,j--)
	{
		temp = s[i];
		s[i] = s[j];
		s[j] = temp;
	}
}
void reverse_words_in_string(char *s)
{
	int i=0;
	int j=0;
	/*
	 * 1st step
	 * In below while loop , string becomes "erehw ereht si a lliw ereht si a yaw"
	 */
	while(*s)
	{
		if( *(s+j) == ' ' || *(s+j) == '\0')
		{
			reverse( s+i, j-i );
			i = j+1;
		}
		if( *(s+j) == '\0')
		{
			break;
		}
		j++;
	}
	/*
	 * 2nd Step
	 */
	reverse(s,strlen(s)); 
}
Find the last word in a string
If given string is "Dreams don't work unless you do "
Output needed : "do"
To get the desired output we will use one pointer which points at the end of string and we will transverse it till we get our first blank space between last 2 words in string.
char* last_word_in_string(char *s)
{
	int i=0;
	char* last;
	const int len= strlen(s) -1;
	char *j = s + len;
/*
 * If last letter of string is blank space then it will be avoided.
 */
	if (*(s+len) == ' ')
	{
		j = j-1;
	}
	while(*j)
	{
		if ( *j== ' ')
		{
			j++;
			break;
		}
		j--;
		i++;
	}
	return j;
}
 
							